$9c-3a+3a$
$9a^4-30a^2b^3+25b^6$
$\int\frac{16x^3+64x}{4x+1}dx$
$cos\:.tan=1$
$\frac{dy}{dx}=\left(\sec\left(x\right)\right)^2-\left(\tan\left(x\right)\right)y+y^2$
$x^4-4x^4$
$a^2-a^4+a^6-a^8$
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