$x\cdot\frac{dy}{dx}+3y=\frac{1}{x}$
$2x^3-3x^2+x-6\::\:2x^2-x+1$
$\sqrt{27a^7}$
$3x-3>0$
$\frac{2y^6+10y^3+9y^2}{-y^2}$
$\cos\left(x\right)+\cos\left(x\right)^2+\cos\left(x\right)^3$
$\frac{dy}{dx}\:\left(2x^3+1\right)^x$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!