$\frac{3}{25}ab+\frac{1}{10}ab$
$\left(9a^9\right)^2$
$-5.38\cdot1.2$
$\frac{x^2}{6x}$
$4=\left(\tan\alpha-\cot\alpha\right)\tan\alpha+2$
$\frac{x^2+11x+10}{x+1}$
$\frac{2x^3+6x^2-x-3}{x^3+3x^2+x-3}$
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