$\lim_{x\to-1}\left(\frac{x^2+4x-3}{x+1}\right)$
$3sin\left(\frac{t}{3}\right)+in\left(\frac{t}{3}+6\pi\right)$
$\left(3x^3+2x\right)+\left(5+6x^2-x^3\right)$
$2\:=\:e^{-3}+c$
$\log_{10}\left(x+3\right)=2$
$-17+25-\left(-58\right)$
$\frac{x\left(2x+3\right)}{x+1}$
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