$\frac{d}{dx}sec^2x-tan^2x$
$\left(8x^2y^5z\right)^2$
$a^2+a^2-4ab$
$\lim_{x\to\infty}\left(\frac{x^3+e^x}{6x^3+4x}\right)$
$61-5+1$
$- \frac { 9 x } { 3 x ^ { 2 } }$
$9x^2-12x+14$
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