$0.33^{10}$
$-2x^2+12x+40$
$6+2\cdot3-[\left(-7\right)\cdot\left(-4\right)]:2+3-1$
$\frac{3x^3+4x^2+3x-1}{x+1}$
$36\cdot\frac{5}{9}$
$6x^2+3y^2=12$
$dx-e^{3x}dy=0$
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