$\int\frac{3}{x^2+4}dx$
$\left(-5500\right)-\left(4200\right)$
$\lim_{x\to\infty}\left(\frac{-3x^2-3x}{\left(x+\frac{1}{2}\right)^2}\right)$
$\frac{x^2}{3x^3\:+6}$
$x^4+8x^3+21x^2+22x+8$
$\frac{3x^4+4}{x^3+3x}$
$1+\left(-20\right)-\left(-7\right)$
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