$\left(140-3x\right)^2$
$1-4b-4b^2$
$\frac{8x+4}{4x+2}$
$-769+-90$
$5+19\cdot4$
$\int_{-1}^2\left(x^2e^{4x}\right)dx$
$\frac{3}{4}x\frac{-2}{9}-1\frac{1}{2}+\frac{7}{8}:\frac{7}{3}$
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