$3\cdot5\cdot5\cdot5\cdot5\cdot5\cdot5$
$x^2-2x+3=0$
$\left(6\cdot10^3\right)\left(2\cdot10^5\right)$
$3a+2b+a+4$
$\int\cot\left(x+1\right)dx$
$sen2x+cos2x+1$
$x\left(x-3\right)^2\left(x+2\right)$
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