$\left(1+\tan^2x\right)\cos^2x-1$
$\lim_{x\to0}-\frac{1}{\left(x-1\right)^2}$
$\lim_{x\to0}\left(\left(1+3x\right)^{\frac{1}{x}}\right)$
$\int\left(\frac{6x^8}{1+x^2}\right)dx$
$\frac{5x^3+8^2-2x+1}{x^2+9x+8}$
$3^2-6x$
$f\left(x\right)=\frac{x^3+3}{x^2}$
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