$\frac{x}{4}+15=20$
$\lim_{x\to1}\frac{1-x+\ln\left(x\right)}{x^3-3x+3}$
$-324\:\cdot\:24$
$\left|-9\right|-8$
$x^3-12x^2+41x-30$
$4\sin\left(x\right)-1=2$
$\ln\left(x\right)=\frac{1}{2}$
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