$3x-1=-4$
$\lim_{x\to0}\left(\frac{2x^3\:-\:5x^2+x}{x^4-x^2}\right)$
$6x-2<8+x$
$\sin^2\left(\frac{1}{4}\right)+\cos\left(a\right)=1$
$\left(8x^3+3y^5\right)\left(8x^3-3y^5\right)$
$x+3a-2x-2$
$8x^{-4}$
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