$\frac{4x^2-1}{2x-1}$
$\frac{\left(1+tan^2\left(\theta\right)\right)\left(sin^2\left(\theta\right)\right)}{tan^2\left(\theta\right)}=1$
$3x^2-7x-7=0$
$\left(n+3\right)\left(n-7\right)$
$x^2+4x-15=0$
$18+580$
$3\left(-3\right)^2-\frac{2}{3}\left(-3\right)+5$
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