$x-4=4x+11$
$\left(2x-6y+2z\right)^2$
$\lim_{x\to\infty}\left(\frac{x+1}{x^2+3}\right)$
$\left(m+7\right)\:\left(m+10\right)$
$x+2>3$
$6+7j-5$
$\left(4x^2-1\right)\left(6x^2-9\right)$
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