$3x^2+6-1$

$\frac{1}{1+3\sin\left(x\right)-4\sin^2\left(x\right)}=\frac{1+\sin\left(x\right)}{1+4\sin\left(x\right)}$

$\lim_{x\to0}\ln\left(x\right)+\frac{1}{x^2}$

$t^3+1$

$4x^2-8x-12$

$\left(2x^2-3x^3+4x^4\right)^2$

$\int_1^2\left(\frac{1}{\sqrt{25-4x^2}}\right)dx$