$\frac{4x^2-8x+3}{36x^3+66x^2+40}$
$\lim_{x\to\infty}\left(\left(\frac{\left(4x+2\right)}{\left(9x-5\right)}\right)^{2x+7}\right)$
$\left(7x+5y\right)\left(49x^2-35xy+25y^2\right)$
$\int e^{x^2-2x+1}dx$
$\frac{2x^3-4x^2+7x}{x^4-4x^3+7x^2-12x+12}$
$x2\:+\:18x\:+\:18\:=\:0\:$
$m^4-m^3-9m^2-11m-4$
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