$\lim_{x\to0}\left(\frac{x^2}{3^x}\right)$
$i ^ { 0 }$
$\lim_{x\to0}\left(\frac{5+\sqrt{x+25}}{x-5}\right)$
$y^3-2y^2-4y+8$
$9\left(-4+x\right)>36$
$\left(4a+8\right)\left(7a+9\right)$
$b=\frac{1n+2n}{10x}$
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