$y=-x^2+4x+1$

$\left(3e^{\left(x\right)}tany\right)dx+\left(\left(1-e^{\left(x\right)}\right)sec^{\left(2\right)}y\right)dy=0$

$-2x^2+22x=60$

$3ab+4ac+7ab-2ac+25$

$\int\sqrt{1+\tan^2\left(ax\right)}\sec^2\left(ax\right)dx$

$-6\left(2x-3y\right)$

$\frac{cos\left(x\right)+1}{sec^2\left(x\right)-1}=\frac{cos\left(x\right)}{sec\left(x\right)-1}$