$\left(-24x^2y^2\right):\left(2x\right)$
$10x^2+30x-70$
$324\cdot10^3$
$\int\frac{\cos x}{\left(\sec x\right)^3}dx$
$x^2-2x-168$
$-2r^2-40r-2=0$
$\left(6x^2+\:9y^3\right)^3$
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