$\int_0^1\left(\frac{\left(x-4\right)}{\left(x^2-5x+6\right)}\right)dx$
$3csc\:u-6=0$
$\frac{s^2+2}{\left(s^2+1\right)^2}$
$2-\left(-30\right)$
$\frac{2x^{3}-13x^{2}+9x-16}{x-6}$
$4s^2+4s+4$
$\frac{3x^{3}+x-11}{x-1}$
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