$\lim_{x\to0}\left(4\ln\left(3+x\right)-\frac{1}{3}\sin\left(4x\right)\right)$
$x^2-16x-17$
$\int\left(x^2+1\right)^6\cdot x$
$-6-\left(-6\right)\left(-7\right)$
$1+\frac{1}{1+\frac{1}{x}}$
$5x+4=x+44$
$a4ab3$
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