$11m^3+6m^2$
$\lim_{x\to\infty}\left(\frac{x^3-1}{x+1}\right)$
$49r^2-81p^2$
$\left(4a-\frac{1}{4}\right)^4$
$\left(3x\:+1\right)\left(3x\:-1\right)$
$0=x^3\left(x^2-10x+25\right)$
$-3+6x-2x-7$
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