$\left(\frac{5}{4}r+\frac{13}{4}\right)\left(\frac{5}{4}r-\frac{13}{4}\right)$

$9h^2+7,3h-12,9h^2+7,4-3,1h^3-5,2$

$cos^2\left(x\right)-cos\left(x\right)-3=0$

$\lim_{x\to\infty}\left(\frac{x\left(3x+1\right)}{x^2+5x+6}\right)$

$8+\left|-15+24\left(-5\right)\right|+\left(-29\right)$

$\int\left(\frac{6e^x}{e^x-3}\right)dx$

$1-6\:+\:1$