$\int\frac{9x^2+6x-9}{x^3-9x}dx$
$\lim_{x\to0}\left(\frac{cos\left(7x\right)-1}{sin\left(6x\right)}\right)$
$y'+y^2=y$
$x-2=10$
$x^2+6x+15>0$
$4v+16-10v$
$\left(-1\right)^5+\left(-1\right)^4+2\left(-1\right)^3-5\left(-1\right)^2+3\left(-1\right)-9$
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