$5\left(7z+4\right)=-5\left(-5z-4\right)+10z$
$-3\:\left(2+5\:-8\right)$
$-18x+8=-x^2$
$\lim_{x\to-3}\left(\frac{5x^2+7x+2}{x+1}\right)$
$-9x-35=10$
$\int\frac{x+2}{x^2+4x+3}dx$
$x^2+10x-13=17$
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