$1=3+8\cos\left(\frac{x}{2}\right)$
$\lim_{x\to\infty}\left(\frac{6x+2}{3x+5}\right)$
$x^{2+12x+36}$
$a+\frac{2a+2b}{5}$
$4a-3a-2$
$x^4-5x^2-x+16;x=9$
$\frac{x^3+102-2000}{x+10}$
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