$6x^2-4x+6$
$\left(h^4-8\right)\left(h^4-3\right)$
$\left(\frac{m}{3}+3n\right)^2$
$14=6n+6-2n$
$2\sin\:^2\left(x\right)-\sin\:\left(x\right)-1=\frac{\pi\:}{8}$
$\log_{14}\left(-2x+4\right)=\log_{14}\left(-3x-5\right)$
$\int\:\frac{x}{3x\:^2+4}dx$
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