$\left(3x^3+4y^6\right)^3$
$m^4+5m^2+9\:$
$6x^2+15x-9=0$
$\lim_{x\to-2}\left(\frac{-4\left(x+2\right)}{9x^{\frac{5}{3}}}\right)$
$16+\left(-5\right)\left(-5\right)\left(-1\right)$
$\frac{54-6}{6}-2$
$-11k+13-g+5g+7+3k$
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