$\frac{\tan\left(x\right)^2}{\sin\left(x\right)^2}=\sec\left(x\right)^2$
$\sqrt[5]{\frac{-3125t^5}{y^{40}}}$
$\cos\:^2x+3\sin\:\left(2\right)x=0$
$\sqrt{1+x^{3}}$
$2x\cdot\left(x^2-5x\right)$
$\left(2x^a+13\right)\left(2x^a-8\right)$
$4x^2-20x-24y=-97$
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