$\left(d^2+4\right)y'=12$
$-3sin^2\left(t\right)+3cos^2\left(t\right)$
$\frac{x^2-2x+1}{x^3+x^2-x-1}$
$9cosx-12sin^2xcosx=0$
$16+x=12$
$\left(2^2\right)^{-4}$
$\lim_{x\to\infty}\left(\frac{6x^3-2x+3x^2-1}{6x^3+12x^2-4x}\right)$
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