Find the roots of $16x^2yx^2\cot\left(h\cot\left(h\right)\right)$

Step-by-step Solution

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asinh
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Final answer to the problem

$y=0$
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Step-by-step Solution

How should I solve this problem?

  • Find the roots
  • Solve for x
  • Solve for y
  • Solve for h
  • Find the derivative
  • Solve by implicit differentiation
  • Solve for y'
  • Find dy/dx
  • Derivative
  • Find the derivative using the definition
  • Load more...
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1

Find the roots of the polynomial $16x^2yx^2\cot\left(h\cot\left(h\right)\right)$ by putting it in the form of an equation and then set it equal to zero

$16x^2yx^2\cot\left(h\cot\left(h\right)\right)=0$

Learn how to solve equations problems step by step online.

$16x^2yx^2\cot\left(h\cot\left(h\right)\right)=0$

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Learn how to solve equations problems step by step online. Find the roots of 16x^2yx^2cot(hcot(h)). Find the roots of the polynomial 16x^2yx^2\cot\left(h\cot\left(h\right)\right) by putting it in the form of an equation and then set it equal to zero. When multiplying exponents with same base we can add the exponents. Multiply the equation by the reciprocal of x^{4}. Any expression multiplied by 0 is equal to 0.

Final answer to the problem

$y=0$

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Plotting: $16x^2yx^2\cot\left(h\cot\left(h\right)\right)$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

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