$\left(m+8\right)\left(m+10\right)$
$\frac{6}{x^2-4x+3}-\frac{1}{x-3}=\frac{-2}{4x-4}$
$\left(3b-1\right)\left(3b-5\right)$
$\left(4a^2+5x\right)\left(by-2bc\right)$
$12+\left(-7\right)-\left(-4\right)+5-\left(2\right)$
$7x^{2a+1}y^7=a$
$a^2+2a-7$
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