$16q^{2}+40q+25$
$\left(3-z^2\right)\left(z^3-z+5\right)$
$\frac{dy}{dx}=\:x+\frac{3y}{x}$
$\left(8a-b+c^2\right)^2$
$\frac{dy}{dx}=3x^7y^6$
$a^2-30ad$
$3\left(2\right)^2+-2\left(2\right)^3+3\left(1\right)+2\left(1\right)-300$
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