$3a^2b^2\:por\:-4xy$
$x^4+27x=0$
$10\cdot10\cdot10$
$x\frac{dy}{dx}+y=\frac{1}{1+x^2}$
$9x^2-7x\le5+3x+9x^2$
$f\left(x\right)=\left(x^2-9\right)\left(16-x^4\right)$
$\frac{3}{4}+\:\int_1^x\:\left(\frac{15}{8}-\frac{9}{8}\right)\:dx$
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