$\int\frac{1}{\left(x+3\right)^4}dx$
$\ln\left(x\cdot y\right)=e^{x-1}$
$7\cdot1732$
$+8-\left|\left(+5\right)-\left(-9\right)\right|$
$x^2+y^2+3x+5y-1=0$
$-2x^2+3x+2x^2-3x$
$\int\left(-3\left(4x-7\right)^8\right)dx$
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