$\left(10a-7\right)\left(10a+7\right)$
$x^2+14x+40$
$24>4x$
$\lim_{x\to0}\left(\left(\frac{1}{\tan\left(x\right)}\right)-\frac{1}{x}\right)$
$a^3\:-\:3a^2b\:+\:4ab^2\:\:por\:\:a^2b\:-\:2ab^2\:+\:10b^3$
$\left(_{-15p}\right)^0$
$\frac{3x^2+2x-8}{x^2+2}$
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