$\int\frac{x^4+1}{x^2\left(x+1\right)^2}dx$
$y'=\left(e^x+2\right)ln\left|y^{-1}\right|^{-1}$
$\left(2m^2+n\right)^2$
$27x^5-15x^3+12x^2$
$4g+3g$
$6y-8y+\left(-3\right)+\left(-4\right)$
$\lim_{x\to0}\left(\frac{\ln\left(x\right)^3}{x^2-1}\right)$
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