$\sqrt{24^2+7^2}-3^2$

$x^6+1^6$

$\sec\left(x\right)^2+\cot\left(x\right)^2-\csc\left(x\right)^2$

$\int x^5\cdot\left(x^3+1\:\right)^2dx$

$y^{'\:}-3y=6$

$\frac{x^{5\left(5\right)+3}-y^{5\left(5\right)+30}}{x^{\left(5\right)-1}-y^{\left(5\right)+2}}$

$\lim_{x\to\infty}\frac{\arctan\left(x^4\right)}{x^5}$