$2-4n$

$1-\left(\cos\left(x\right)\cdot\tan\left(x\right)\right)^2$

$5e^{5\infty}$

$\left(sin\left(x\right)\right)^2+2\left(sin\left(x\right)\right)-2=0$

$\left(-64\right)\::\:2\::\:\left(-8\right)\::\:\left(-2\right)$

$\left(-10\right)+\left(-8\right)-\left(+1\right)-\left(-6\right)+\left(-30\right)$

$6\left(x-12\right)$