$4x^2+40x+16$
$3^{2x-6}=81$
$\left(x-8\right)\left(7x+4\right)$
$w=xy+xz+yz$
$\left(9ab-8cd\right)^2$
$i\:4+i\:2-3i+2$
$\frac{dy}{dx}=\frac{2xy}{1+x^2}=\frac{1}{\left(1+x^2\right)^2}$
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