$\frac{\sin x-\sin^3x}{\cos^3x}=\tan x$
$\frac{xy^6}{xy^8}$
$12-\left(+16-11+3\right)$
$5x^2-2x-7=0$
$a\cdot a\cdot a\cdot b\cdot b$
$\lim_{x\to-1}\left(\frac{x^2+x}{x+1}\right)$
$\left(a+3\right)^2+2\left(a-3\right)+1$
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