$y^6=c\left(x+1\right)$
$10-10+9c$
$7sin\left(2x\right)=cos\left(x\right)$
$x^2\:-\:6x\:=\:16$
$-9+8-1+4+3-2-9$
$8y^2-5y+7\left(2y^2\right)+7y+10$
$\frac{1-\sin x}{\cos x}=0$
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