$\frac{\sqrt[4]{8}}{\sqrt[3]{2^2}}\cdot\:\frac{\sqrt[5]{20}}{\sqrt[6]{5.2}}$
$3\left(2-5\right)+2\:\left(-3-\left(-1\right)\right)$
$64x^2y^6\:-\:32x^9y^3\:+\:4x^{16}$
$2.1+0.95$
$\left(x-\frac{2}{3}\right)\left(x-\frac{1}{6}\right)$
$x^2=4z$
$2xy'-y=x^3-x$
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