$\int\left(5x^3\right)\left(x^3-1\right)^4dx$
$-3x-5\le4-x$
$8x+5=7x-4$
$\frac{d}{dx}\left(\frac{\left(x\left(x^2-9\right)^2\right)}{x-8}\right)$
$3ab^2\left(3a-5ab+2b^2\right)$
$3k^2.4k^3$
$\int x^2\cdot sen\left(2x-3\right)dx$
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