$\frac{d}{dx}8\sqrt{3-x^2}$
$9\cos\:^2\left(x\right)-\cos\:\left(2x\right)\cdot\:\:cos\left(x\right)=-4cos\left(x\right)$
$\left(3t^2-2\right)\left(4t-3s\right)$
$-88.02+0,067$
$\frac{6}{1-x^3}$
$\frac{d}{dx}\:\frac{7tant}{3+3sect}$
$x\:-\:4y\:=\:3$
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