$\:x\:\frac{dy}{dx}\:+6y=3xy^{\frac{4}{3}}$
$\int\frac{x-12}{\left(x-5\right)\left(x+2\right)}dx$
$\:\frac{\left(4x^6\:y\right)}{\left(-2x^3\:y\right)}\:$
$4x^2-2\cdot\sqrt{3\cdot x}+1$
$x^2+9x+5$
$\int\frac{5x\sqrt[4]{3-4x^2}}{2}dx$
$3.x-12<x+3$
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