$x+12=3x+20$
$x^2-8x+41$
$16+8\left(x+y\right)+\left(x+y\right)^2$
$7\cdot5-17\cdot2$
$-14+20x+8x^2$
$\frac{dy}{dx}=\frac{\sec^2\left(x\right)}{1+2y}$
$3x+9<7-5x$
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