$\int\frac{1}{x\left(x+1\right)^4}dx$

$21\frac{1}{4}x^2-2$

$\int x\sqrt{4x^2+40x+96}dx$

$w=\frac{\tan\left(u\right)}{\tan\left(u\right).\cos\left(u\right)+\sin\left(v\right)}$

$\left(8\cdot19\right)+\left(4\cdot16\right)-\left(2\cdot19\right)$

$\frac{d}{dx}7^{3x^2-1}$

$4\cdot0-5$