$\sin\left(x\right)^2=\frac{1}{4}$

$\lim_{x\to5}\left(\frac{x^2-25}{10-2x}\right)$

$2x+5x^2-4x^2-x^2$

$6a^8+12a^6-18a^9+24a^2$

$\int_8^{\infty}\left(\frac{1}{\left(x-7\right)^{\frac{3}{2}}}\right)dx$

$a^3-6ab^2+9a-15a^2b-8a+5$

$5+2\left[3-4\left(6+2\right)+5\left(3-2\right)-8\right]+3\left(6+4\right)$