$\frac{tan^2x+1}{1-sec^2x}$
$18m^4n^2n^6m^8$
$\left(\frac{8d}{6^2}^8\right)^2$
$x^3+9x^2+26x+24$
$x-5>3x$
$xy'=45y$
$\frac{1}{5}-\frac{2}{3}x\:+\:\frac{3}{4}x+2y\:-\:\frac{3}{7}-4x+3y$
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